6x^2+96x+2304=1926

Solution for 6x^2+96x+2304=1926 equation:

6x^2+96x+2304=1926

We move all terms to the left:

6x^2+96x+2304-(1926)=0

We add all the numbers together, and all the variables

6x^2+96x+378=0

a = 6; b = 96; c = +378;
Δ = b2-4ac
Δ = 962-4·6·378
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-12}{2*6}=\frac{-108}{12}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+12}{2*6}=\frac{-84}{12}
=-7
$